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WebDec 28, 2024 · You should go the other way, apply the logarithm to the original equation to get $$ \log_2n+\log_2\log_2n=\log_2(10^6)\approx 20 $$ The logarithm of numbers around 20 is between 4 and 5, so that $\log_2n\approx 16\iff n=64\cdot 1024$ appears reasonable. The result of $2^{16}\cdot 16=2^{20}=(1024)^2$ is slightly larger than the target value, … WebMar 9, 2024 · Charts Of Contents watch Introduction Best Books for Data Organizational and Algorithms 1. Induction to Algorithms 2. Information Structures and Automatic Made Easy 3. Calculating 4. Grokking Algorithms 5. unh intern program
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